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Remove path argument from cmd_execute()

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It is always equal to argv[0] (or not used on Windows).
This commit is contained in:
Romain Vimont
2019-11-27 13:41:47 +01:00
parent 8dc11a0286
commit 73e8ec1b35
4 changed files with 5 additions and 6 deletions
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4
app/src/sys/unix/command.c
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@@ -21,7 +21,7 @@
#include "util/log.h"
enum process_result
cmd_execute(const char *path, const char *const argv[], pid_t *pid) {
cmd_execute(const char *const argv[], pid_t *pid) {
int fd[2];
if (pipe(fd) == -1) {
@@ -52,7 +52,7 @@ cmd_execute(const char *path, const char *const argv[], pid_t *pid) {
// child close read side
close(fd[0]);
if (fcntl(fd[1], F_SETFD, FD_CLOEXEC) == 0) {
execvp(path, (char *const *)argv);
execvp(argv[0], (char *const *)argv);
if (errno == ENOENT) {
ret = PROCESS_ERROR_MISSING_BINARY;
} else {

3
app/src/sys/win/command.c
View File

@@ -19,8 +19,7 @@ build_cmd(char *cmd, size_t len, const char *const argv[]) {
}
enum process_result
cmd_execute(const char *path, const char *const argv[], HANDLE *handle) {
(void) path;
cmd_execute(const char *const argv[], HANDLE *handle) {
STARTUPINFOW si;
PROCESS_INFORMATION pi;
memset(&si, 0, sizeof(si));